精品深夜AV无码一区二区_伊人久久无码中文字幕_午夜无码伦费影视在线观看_伊人久久无码精品中文字幕

代寫COMP9021、代做Python程序語(yǔ)言

時(shí)間:2024-03-27  來源:  作者: 我要糾錯(cuò)



COMP9021 Principles of Programming
Term 1, 2024
Assignment 1
Worth 13marks and due Week 7 Monday @ 10am
1. General Matters
1.1 Aim
The purpose of this assignment is to:
• develop your problem-solving skills.
• design and implement the solution to a problem in the form of a medium sized Python program.
• practice the use of arithmetic computations, tests, repetitions, lists, and strings.
• use procedural programming.
1.2 Marking
This assignment is worth 13 marks distributed approximately as follows:
1.50 marks for "I don't get what you want, sorry mate!"
3.50 marks for "Hey, ask me something that's not impossible to do!"
2.25 marks for "Please convert ***"
2.50 marks for "Please convert *** using ***"
3.25 marks for "Please convert *** minimally"
 ----------------------------------------------------------------------
13.00 marks total
Your program will be tested against several inputs. For each test, the automarking script will let your
program run for 30 seconds. The outputs of your program should be exactly as indicated.
2
1.3 Due Date and Submission
Your program will be stored in a file named roman_arabic.py. The assignment can be submitted
more than once. The last version just before the due date and time will be marked (unless you submit late
in which case the last late version will be marked).
Assignment 1 is due Week 7 Monday 25 March 2024 @ 10:00am (Sydney time)
Note that late submission with 5% penalty per day is allowed up to 5 days from the due date, that is, any
late submission after Week 7 Saturday 30 March 2024 @ 10:00am will be discarded.
Make sure not to change the filename roman_arabic.py while submitting by clicking on [Mark]
button in Ed. It is your responsibility to check that your submission did go through properly using
Submissions link in Ed otherwise your mark will be zero for Assignment 1.
1.4 Reminder on Plagiarism Policy
You are permitted, indeed encouraged, to discuss ways to solve the assignment with other people. Such
discussions must be in terms of algorithms, not code. But you must implement the solution on your own.
Submissions are scanned for similarities that occur when students copy and modify other people’s work or
work very closely together on a single implementation. Severe penalties apply.
2. Description
You will design and implement a program that prompts the user for an input with:
How can I help you?
User input should be one of three possible kinds:
Please convert ***
Please convert *** using ***
Please convert *** minimally
If the user input is not of this form, with any occurrence of *** an arbitrary nonempty sequence
of non-space symbols, then the program should print out:
I don't get what you want, sorry mate!
and stop.
3
2.1 First Kind of Input
In case the user inputs Please convert ***, then *** should be either a strictly positive
integer (whose representation should not start with 0) that can be converted to a Roman number
(hence be at most equal to 3999), or a valid Roman number; otherwise, the program should
print out:
Hey, ask me something that's not impossible to do!
and stop.
If the input is as expected, then the program should perform the conversion, from Arabic to
Roman or from Roman to Arabic, and print out the result in the form:
Sure! It is ***
2.2 Second Kind of Input
In case the user inputs Please convert *** using ***, then the first *** should be
a strictly positive integer (whose representation should not start with 0) or a sequence of
(lowercase or uppercase) letters and the second *** should be a sequence of distinct
(lowercase or uppercase) letters.
Moreover:
• the second *** is intended to represent a sequence of so-called generalised
Roman symbols. The classical Roman symbols corresponding to the sequence
MDCLXVI, whose rightmost element is meant to represent 1, the second rightmost
element 5, the third rightmost element 10, etc.
• if it is not an integer, the first *** is intended to represent a so-called generalised
Roman number, that is, a sequence of generalised Roman symbols that can be decoded
using the provided sequence of generalised Roman symbols similarly to the way Roman
numbers are represented.
If that is not the case, or if it is not possible to convert the first *** from Arabic to generalised
Roman or from generalised Roman to Arabic, then the program should print out:
Hey, ask me something that's not impossible to do!
and stop.
4
If the input is as expected and the conversion can be performed, then the program should indeed perform
the conversion, from Arabic to generalised Roman or from generalised Roman to Arabic, and print out the
result in the form:
Sure! It is ***
2.3 Third Kind of Input
In case the user inputs Please convert *** minimally, then *** should be a sequence
of (lowercase or uppercase) letters. The program will try and view *** as a generalised Roman
number with respect to some sequence of generalised Roman symbols. If that is not possible,
then the program should print out:
Hey, ask me something that's not impossible to do!
and stop.
Otherwise, the program should find the smallest integer that could be converted from ***,
viewed as some generalised Roman number, to Arabic, and output a message of the form
Sure! It is *** using ***
5
3. Sample Outputs (or Test Cases)
Here are a few tests together with the expected outputs. The outputs of your program should be exactly
as shown:
$ python3 roman_arabic.py
How can I help you? Please do my assignment...
I don't get what you want, sorry mate!
$ python3 roman_arabic.py
How can I help you? please convert 35
I don't get what you want, sorry mate!
$ python3 roman_arabic.py
How can I help you? Please convert 035
Hey, ask me something that's not impossible to do!
$ python3 roman_arabic.py
How can I help you? Please convert 4000
Hey, ask me something that's not impossible to do!
$ python3 roman_arabic.py
How can I help you? Please convert IIII
Hey, ask me something that's not impossible to do!

6
$ python3 roman_arabic.py
How can I help you? Please convert IXI
Hey, ask me something that's not impossible to do!
$ python3 roman_arabic.py
How can I help you? Please convert 35
Sure! It is XXXV
$ python3 roman_arabic.py
How can I help you? Please convert 1982
Sure! It is MCMLXXXII
$ python3 roman_arabic.py
How can I help you? Please convert 3007
Sure! It is MMMVII
$ python3 roman_arabic.py
How can I help you? Please convert MCMLXXXII
Sure! It is 1982
$ python3 roman_arabic.py
How can I help you? Please convert MMMVII
Sure! It is 3007

7
$ python3 roman_arabic.py
How can I help you? Please convert 123 by using ABC
I don't get what you want, sorry mate!
$ python3 roman_arabic.py
How can I help you? Please convert 123 ussing ABC
I don't get what you want, sorry mate!
$ python3 roman_arabic.py
How can I help you? Please convert XXXVI using VI
Hey, ask me something that's not impossible to do!
$ python3 roman_arabic.py
How can I help you? Please convert XXXVI using IVX
Hey, ask me something that's not impossible to do!
$ python3 roman_arabic.py
How can I help you? Please convert XXXVI using XWVI
Hey, ask me something that's not impossible to do!
$ python3 roman_arabic.py
How can I help you? Please convert I using II
Hey, ask me something that's not impossible to do!

8
$ python3 roman_arabic.py
How can I help you? Please convert _ using _
Hey, ask me something that's not impossible to do!
$ python3 roman_arabic.py
How can I help you? Please convert XXXVI using XVI
Sure! It is 36
$ python3 roman_arabic.py
How can I help you? Please convert XXXVI using XABVI
Sure! It is 306
$ python3 roman_arabic.py
How can I help you? Please convert EeDEBBBaA using fFeEdDcCbBaA
Sure! It is 49036
$ python3 roman_arabic.py
How can I help you? Please convert 49036 using fFeEdDcCbBaA
Sure! It is EeDEBBBaA
$ python3 roman_arabic.py
How can I help you? Please convert 899999999999 using
AaBbCcDdEeFfGgHhIiJjKkLl
Sure! It is Aaaabacbdcedfegfhgihjikjlk

9
$ python3 roman_arabic.py
How can I help you? Please convert ABCDEFGHIJKLMNOPQRST using
AbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStT
Sure! It is 11111111111111111111
$ python3 roman_arabic.py
How can I help you? Please convert 1900604 using LAQMPVXYZIRSGN
Sure! It is AMAZING
$ python3 roman_arabic.py
How can I help you? Please convert ABCD minimally using ABCDE
I don't get what you want, sorry mate!
$ python3 roman_arabic.py
How can I help you? Please convert ABCD minimaly
I don't get what you want, sorry mate!
$ python3 roman_arabic.py
How can I help you? Please convert 0I minimally
Hey, ask me something that's not impossible to do!
$ python3 roman_arabic.py
How can I help you? Please convert ABAA minimally
Hey, ask me something that's not impossible to do!

10
$ python3 roman_arabic.py
How can I help you? Please convert ABCDEFA minimally
Hey, ask me something that's not impossible to do!
$ python3 roman_arabic.py
How can I help you? Please convert MDCCLXXXVII minimally
Sure! It is 1787 using MDCLXVI
$ python3 roman_arabic.py
How can I help you? Please convert MDCCLXXXIX minimally
Sure! It is 1789 using MDCLX_I
$ python3 roman_arabic.py
How can I help you? Please convert MMMVII minimally
Sure! It is 37 using MVI
$ python3 roman_arabic.py
How can I help you? Please convert VI minimally
Sure! It is 4 using IV
$ python3 roman_arabic.py
How can I help you? Please convert ABCADDEFGF minimally
Sure! It is 49269 using BA_C_DEF_G
$ python3 roman_arabic.py
How can I help you? Please convert ABCCDED minimally
Sure! It is 1719 using ABC_D_E
11
4. Hints
4.1 Explaining the following example of the third kind of input
(Please convert *** minimally):
$ python3 roman_arabic.py
How can I help you? Please convert ABCADDEFGF minimally
Sure! It is 49269 using BA_C_DEF_G
First, remember the two important Roman numeral rules below:
1. A Roman symbol is repeated three times but not more than that. However, the symbols V (5),
L (50) and D (500) are never repeated.
2. The Roman symbols V (5), L (50) and D (500) are never written to the left of a symbol of
greater value, i.e., V (5), L (50) and D (500) are never subtracted. The symbol I (1) can be
subtracted from V (5) and X (10) only. The symbol X can be subtracted from L (50) and C (100)
only.
Note also that "minimally" means we are looking for a generalised Roman symbols that can
convert the given numeral into a smallest integer number.
Let us start assigning Roman numeral values from the right-hand side such that the value is
minimum.
Starting with F, we can see it is repeated and we have to assign the minimum value to FGF in
order to assign the minimum value to F. From a number of various combinations, we know
that the only possible solution here is F=10 and G=1 (try out combinations of 1, 5, 10 here to
see why this is the right one). Thus FGF=19.
Let us move now to the next element, which is E. We also need to consider the element after
E in order to assign a smaller combination, if possible, in this case. The next element is D,
which is repeated and therefore cannot be less than E. Thus, we assign E the smallest number
not used yet, which is 50. Moving on to D, since it is repeated, it cannot be greater than the
next element A. Thus, we assign the smallest number not yet used which is 100 to D.
Till now, our number DDEFGF is resulting in 269 using DEF_G (value 5 not assigned).
The next element is A and it is repeated. To assign a value to A, we must assign a value so that
ABCA does not violate Roman numeral rules. That is, A < B and B > C. Because of AB (A and B
being next to each other), we cannot assign A as 500 (500 cannot be subtracted from any
number).
12
Let us say we assign 1000 to A. Then B can be either 5000 or 10000. B cannot be 5000 because
that would mean C can only be 500. Also, B cannot be 10000 as it would mean C should be
5000 or 500 (both are invalid assignments).
Let us try to assign 10000 to A (it cannot be assigned 5000 since it is repeated). B can be either
50000 or 100000. If B is 50000, C can be either 5000, 1000 or 500. C cannot be 5000 or 500
(since they be subtracted from any number). C can be 1000.
Consequently, the smallest we can come up with here is 10000 for A, 50000 for B, and 1000
for C, and ABCA = 50000 - 10000 + 10000 - 1000 = 49000.
Thus, the total becomes 49269 using BA_C_DEF_G (values 5, 500 and 5000 not assigned).
4.2 More examples about the third kind of input
(Please convert *** minimally):
$ python3 roman_arabic.py
How can I help you? Please convert AZERTY minimally
Sure! It is 444 using ZAREYT
$ python3 roman_arabic.py
How can I help you? Please convert XXXVVVIII minimally
Sure! It is 333 using X_V_I
$ python3 roman_arabic.py
How can I help you? Please convert AhZhJ minimally
Sure! It is 691 using Ah_Z_J
$ python3 roman_arabic.py
How can I help you? Please convert BCBC minimally

請(qǐng)加QQ:99515681  郵箱:99515681@qq.com   WX:codehelp




 

標(biāo)簽:

掃一掃在手機(jī)打開當(dāng)前頁(yè)
  • 上一篇:代做CMPSC 443、代寫Project 2: Buffer Overflows
  • 下一篇:INFO-5060代做、代寫C++程序語(yǔ)言
  • 無相關(guān)信息
    昆明生活資訊

    昆明圖文信息
    蝴蝶泉(4A)-大理旅游
    蝴蝶泉(4A)-大理旅游
    油炸竹蟲
    油炸竹蟲
    酸筍煮魚(雞)
    酸筍煮魚(雞)
    竹筒飯
    竹筒飯
    香茅草烤魚
    香茅草烤魚
    檸檬烤魚
    檸檬烤魚
    昆明西山國(guó)家級(jí)風(fēng)景名勝區(qū)
    昆明西山國(guó)家級(jí)風(fēng)景名勝區(qū)
    昆明旅游索道攻略
    昆明旅游索道攻略
  • 短信驗(yàn)證碼平臺(tái) 理財(cái) WPS下載

    關(guān)于我們 | 打賞支持 | 廣告服務(wù) | 聯(lián)系我們 | 網(wǎng)站地圖 | 免責(zé)聲明 | 幫助中心 | 友情鏈接 |

    Copyright © 2025 kmw.cc Inc. All Rights Reserved. 昆明網(wǎng) 版權(quán)所有
    ICP備06013414號(hào)-3 公安備 42010502001045

    精品深夜AV无码一区二区_伊人久久无码中文字幕_午夜无码伦费影视在线观看_伊人久久无码精品中文字幕
    <samp id="e4iaa"><tbody id="e4iaa"></tbody></samp>
    <ul id="e4iaa"></ul>
    <blockquote id="e4iaa"><tfoot id="e4iaa"></tfoot></blockquote>
    • <samp id="e4iaa"><tbody id="e4iaa"></tbody></samp>
      <ul id="e4iaa"></ul>
      <samp id="e4iaa"><tbody id="e4iaa"></tbody></samp><ul id="e4iaa"></ul>
      <ul id="e4iaa"></ul>
      <th id="e4iaa"><menu id="e4iaa"></menu></th>
      久久精品久久国产| 亚洲成人av免费看| 久久久久久久久久久久久av| 亚洲av无码一区二区三区人| 国产一区二区三区三州| 在线观看岛国av| 欧美日韩在线观看成人| a级在线免费观看| 亚洲欧美日韩精品永久在线| 欧美一区二区在线观看视频| 国产乱码在线观看| 91午夜精品亚洲一区二区三区| 欧美一区二区三区观看| www.亚洲黄色| 亚洲色婷婷一区二区三区| 四虎成人精品永久免费av| 久久国产柳州莫菁门| 国产女人爽到高潮a毛片| jizz国产在线观看| 91成人在线观看喷潮蘑菇| 这里只有精品免费视频| 深爱五月激情五月| 欧美日韩国产一二三区| 久久99999| 久久成人国产精品入口| 久久无码人妻精品一区二区三区 | 中文字幕精品一区二区三区在线| 精品无码一区二区三区的天堂| 99热这里只有精品2| 亚洲国产日韩在线一区| 亚洲第一页在线观看| 午夜精品一区二区三级视频| 日韩精品一区三区| 日本va欧美va国产激情| 色噜噜日韩精品欧美一区二区| 欧美成人aaaaⅴ片在线看| 你懂的网站在线| 日韩丰满少妇无码内射| 熟妇人妻久久中文字幕| 亚洲a视频在线观看| 亚洲GV成人无码久久精品| 欧美人妻精品一区二区免费看| 久久av无码精品人妻系列试探| 国产黄色片免费| 国产又大又黄的视频| 久久一区二区三区视频| 日本在线观看视频一区| 五月天激情丁香| 夜夜爽久久精品91| 国产精品久久久久久无人区| 国产又大又黄又爽| 欧美视频一区二区在线| 四虎精品一区二区| 99国产精品欲| 久久久久亚洲av成人片| 无码人妻一区二区三区精品视频| 一区二区视频在线免费观看| 99在线精品视频免费观看软件| 国产天堂av在线| 日韩一级在线视频| 99久久精品国产一区色 | 欧美精品一二三四区| 无码人妻aⅴ一区二区三区69岛| 亚洲欧美国产日韩综合| 国产一二三区av| 天天操天天射天天舔| 99视频只有精品| 久久一二三四区| 亚洲精品国偷拍自产在线观看蜜桃| www国产一区| 激情久久综合网| 五月天中文字幕在线| 成人一二三四区| 日韩免费av一区| 97人妻精品一区二区三区| 国产一级免费视频| 九九精品视频免费| 亚洲精品一区二区三区四区| 韩国av永久免费| 中文字幕观看在线| 国产视频第一页| 亚洲精品久久久中文字幕| 久久久久人妻一区精品色| 911av视频| 免费在线观看亚洲| 91色国产在线| 天天操天天舔天天干| 精品无码久久久久久久| 亚洲人成人无码网www国产| 毛片网站免费观看| v天堂中文在线| 我不卡一区二区| 激情五月婷婷基地| 丰满熟女一区二区三区| 中文字幕 欧美激情| 人妻91麻豆一区二区三区| 国产午夜久久久| 91香蕉视频污在线观看| 亚洲av片在线观看| 免费观看一区二区三区| 亚洲欧洲日韩综合| 日日夜夜综合网| 久久久久久久久久久久久av | 欧美激情 亚洲| 国产精品成人久久久| 亚洲欧美视频在线播放| 婷婷五月综合激情| 欧美人妻精品一区二区三区 | 中文字幕在线播出| 日本黄色中文字幕| 国产一级大片在线观看| 成人午夜精品福利免费| 99热在线观看精品| 亚洲乱色熟女一区二区三区| 亚洲AV无码成人精品区东京热| 欧美一级特黄高清视频 | 国产三级在线观看视频| 波多野结衣 久久| 一级α片免费看刺激高潮视频| 在线不卡一区二区三区| 精品国自产拍在线观看| 精品国产欧美日韩不卡在线观看| 国产精品久久久久精| 91色国产在线| 不卡的在线视频| 国产亚洲色婷婷久久99精品91| 国产日韩久久久| 国产熟女一区二区三区四区| 国产精品久久婷婷| 黄色一区二区视频| 久久中文字幕免费| 欧美性生交xxxxx| 日韩一区免费视频| 在线免费播放av| 97人妻精品一区二区三区| 91av免费观看| 国产日韩在线观看一区| 久久久久亚洲av无码专区首jn| 精品一级少妇久久久久久久| 男女男精品视频站| 天堂成人在线视频| 亚洲精品综合网| 国产精品久久影视| 欧美精品亚洲精品日韩精品| 欧美极品视频在线观看| 小嫩苞一区二区三区| jlzzjlzz亚洲女人18| 久久精品一区二区三| 天堂网成人在线| 亚洲综合激情视频| 精品国产国产综合精品| 日日噜噜噜噜人人爽亚洲精品| 亚洲日本黄色片| 丁香六月天婷婷| 欧美成人精品欧美一级| 亚洲精品无码久久久久| 黄色片在线免费| 宅男噜噜噜66国产免费观看| 非洲一级黄色片| 麻豆亚洲av成人无码久久精品| 在线观看av网页| 国产污视频在线看| 亚欧激情乱码久久久久久久久| 国产激情视频在线播放| 日韩在线观看视频一区| 丰满熟女人妻一区二区三| 日韩欧美成人一区二区三区| 99精品在线看| 日日骚一区二区三区| 亚洲精品77777| 精品久久久久一区二区 | 亚洲专区区免费| 久久成人小视频| 亚洲免费不卡视频| 免费无码毛片一区二区app| 亚洲一区二区蜜桃| 久久久久久无码午夜精品直播 | 中文字幕在线日本| 久久久国产一级片| 亚洲天堂成人av| 日本少妇激三级做爰在线| 国产精品九九九九| 中文字幕人妻一区二区三区在线视频| 黄色一级大片在线免费看国产| 亚洲熟妇一区二区三区| 日韩av综合在线| 国产一级做a爱片久久毛片a| 亚洲女人久久久| 欧美三级午夜理伦| 国产三级午夜理伦三级| 99超碰在线观看| 亚洲一区二区福利视频| 在线观看av网页| 五月激情五月婷婷| 天天综合永久入口| 少妇一级淫免费放| 天堂成人在线视频| 少妇欧美激情一区二区三区| 日韩成人av一区二区| 日韩专区第一页|